are vptr and vtable inherited from base class?

As can be seen, D3 introduces a new virtual function, @function3(), in the middle of the chain of inheritance. I am wondering what is happening with *--vptr and vtable when this happens. D3 is a 'kind of' a new base class now,

class Base {
public:
    virtual void function1() { std::cout << "Base func1()\n"; };
    virtual void function2() { std::cout << "Base func2()\n"; };
};

class D1 : public Base {
public:
    virtual void function2() { std::cout << "D1 func2()\n"; };
};

class D2 : public D1 {
public:
    virtual void function1() { std::cout << "D2 func1()\n"; };
};

class D3 : public D2 {
public:
    virtual void function2() { std::cout << "D3 func2()\n"; };
    virtual void function3() { std::cout << "D3 func3()\n"; };
};

class D4 : public D3 {
public:
    virtual void function1() { std::cout << "D4 func1()\n"; };
    virtual void function3() { std::cout << "D4 func3()\n"; };
};

int main() {
    D3 d3;  
}

but when I see vtable entries, what I can see are function1(), function2(). I thought entries have to be function2(), function3(). Why can't I get what I thought?

The vtable contains all inherited virtual functions and any newly introduced one.

Here is the vtable for D3 generated by MSVC:

const D3::`vftable' DD  FLAT:const D3::`RTTI Complete Object Locator'  ; D3::`vftable'
        DD      FLAT:virtual void D2::function1(void)
        DD      FLAT:virtual void D3::function2(void)
        DD      FLAT:virtual void D3::function3(void)

The reason why the debugger doesn't show all of them might be a bug or a limitation.