Evaluate truthiness in Java

I am writing an interactive console app in Java. I need to ask the user questions with Boolean responses, however, Scanner.in.nextBoolean() is rather brittle in that it throws exceptions on incorrect input, so wrapping it in a method seems like a good idea. I could just use a try/catch block and insist on the user typing "true" or "false" to answer and catch the typos. But then I thought I could use Scanner.in.next() or Scanner.in.nextLine() and evaluate the returned string for truthiness using something like parseBoolean(String s).

Is there a way to evaluate a string for "truthiness" beyond true/false? That is, "0"/"1" "yes"/"no" would also evaluate to true/false.

What about a custom implementation?

1. Use a map and define all the values for true and false
2. Use a list; true if the value is in the list, otherwise false

public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);

    // Define true and false values
    Map<String, Boolean> truthiness = new HashMap<>();

    truthiness.put("yes", true);
    truthiness.put("1", true);
    truthiness.put("true", true);
    truthiness.put("t", true);
    truthiness.put("ya", true);
    truthiness.put("nein", false);
    //etc

    // Define only the true values
    List<String> trueValues = Arrays.asList("yes", "1", "true", "t", "ya");

    for(int i = 0; i < 5; ++i) {
        String value = sc.nextLine().toLowerCase();

        System.out.println("map: " + truthiness.get(value));
        System.out.println("list: " + trueValues.contains(value));
    }
}

Output

yes
map: true
list: true
1
map: true
list: true
t
map: true
list: true
ya
map: true
list: true
nein
map: false
list: false