How to append each line from 11-20 to each line from 1-10 in VIM

I have a file in which first 10 lines are the columns of a table and the rest 10 lines are the values of each column.

How can I use norm in VIM to append the values after each column names like this:

column1
...
column10
value1
...value10

-->

column1: value1
...
column10: value10

It is a little similar with this(Vim - Copy Nth word of each line, from line 10-100, to end of line), but I don't know how to go to line 1:10 and append the copied lines.

Any idea will be appreciated!

Fairly naive and crude way to do this, but:

:1,10norm! 10j0d$10kA: ^[p

Explanation:

• 1,10norm!: for lines 1 to 10, do the following (the ! means any custom mapping you have will be ignored, thanks to D. Ben Knoble for reminding of this):
• 10j: move down 10 lines
• 0d$: delete the whole line (not including newline)
• 10k: move back up 10 lines
• A:: append (at the end of the line) ': ' (note the trailing space)
• ^[: input escape character, going back to normal mode. This (^[) is a single character and is inputted by typing Ctrl-v then escape, not by typing ^[.
• p: paste the line deleted in step 3

---

Another (copy-pastable) way, (ab)using the substitute command:

:1,10s/\v(.*)\ze(.*\n){10}(.*)/\1: \3/ | 11,20d

which does:

• 1,10s/: for lines 1 to 10, execute the following substitution:
• \v: use very-magic regex mode (see :help \v)
• (.*): capture the entire current line (eg column1)
• \ze: signal the end of the match. This way everything read (and captured) afterwards will not be affected (but can still be read)
• (.*\n){10}: skip 10 (including current) lines, ie skip selector to 10 lines below
• (.*): capture the line (eg value1)
• /: end the 'select' part of the substitute command
• \1: \3: replace with captured groups (eg column1: value1)
• |: command separator
• 11,20d: delete lines 11 to 20