[SOLVED] How to pass a vector of strings to execv

How to pass a vector of strings to execv

I have found that the easiest way to build my program argument list is as a vector of strings. However, execv expects an array of chars for the second argument. What's the easiest way to get it to accept of vector of strings?

Solution

execv() accepts only an array of string pointers. There is no way to get it to accept anything else. It is a standard interface, callable from every hosted language, not just C++.

I have tested compiling this:

std::vector<string> vector;
const char *programname = "abc";

const char **argv = new const char* [vector.size()+2];   // extra room for program name and sentinel
argv [0] = programname;         // by convention, argv[0] is program name
for (int j = 0;  j < vector.size()+1;  ++j)     // copy args
        argv [j+1] = vector[j] .c_str();

argv [vector.size()+1] = NULL;  // end of arguments sentinel is NULL

execv (programname, (char **)argv);