I want to know a field if it does not match a certain string:
Case 1: When the previous node is not *_pcm.h, then l1 gives the path to file l2.
Case 2: When there is no l1 or case 1 is not true, then l is what I need
visit(sec) {
// case 1
case \sources(_, "_SOURCES", [*_, l1:\sourceList(_, _, _, p:/_pcm.h/i, _, _),
l2:\sourceList(_, _, _, n:/_pcm.c/i, _, _), *_]): {
name = determinePath(p, n, f);
}
// case 2
case \sources(_, "_SOURCES", [*_, l:\sourceList(_, _, _, n:/_pcm.c/i, _, _) , *_]): {
path = getPath(f);
}
}
Instead of p:/_pcm.h/i I tried p:!/_pcm.h/i but this does not work
You can not directly express this negation inside a pattern, but here is a workaround by adding a when condition to the case in the case you are transforming (i.e., using => between pattern and action):
data D = d1(str s) | d2(int n);
D transform(D subject){
return visit(subject){
case d1(str s) => d1(s + s) when /abc/ !:= s
}
}
In the case of a more complex case, you can to the test and use a fail to let the case fail.
case d1(str s): { if(/abc/ !:= s) fail; ... }
Hope this solves your problem.