Find date from image/text

I have dates like this and I need regex to find these types of dates

   12-23-2019
   29 10 2019
   1:2:2018
   9/04/2019
   22.07.2019

here's what I did first I removed all spaces from the text and here's what it looks like

   12-23-2019291020191:02:2018

and this is my regex

    re.findall(r'((\d{1,2})([.\/-])(\d{2}|\w{3,9})([.\/-])(\d{4}))',new_text)

it can find 12-23-2019 , 9/04/2019 , 22.07.2019 but cannot find 29 10 2019 and 1:02:2018

You may use

(?<!\d)\d{1,2}([.:/ -])(?:\d{1,2}|\w{3,})\1\d{4}(?!\d)

See the regex demo

Details

• (?<!\d) - no digit right before
• \d{1,2} - 1 or 2 digits
• ([.:/ -]) - a dot, colon, slash, space or hyphen (captured in Group 1)
• (?:\d{1,2}|\w{3,}) - 1 or 2 digits or 3 or more word chars
• \1 - same value as in Group 1
• \d{4} - four digits
• (?!\d) - no digit allowed right after

Python sample usage:

import re
text = 'Aaaa 12-23-2019, bddd   29 10 2019 <===   1:2:2018'
pattern = r'(?<!\d)\d{1,2}([.:/ -])(?:\d{1,2}|\w{3,})\1\d{4}(?!\d)'
results = [x.group() for x in re.finditer(pattern, text)]
print(results) # => ['12-23-2019', '29 10 2019', '1:2:2018']