I have a function, createFile that uses fchmod:
int createFile(char *pFileName) {
int ret;
if ((ret = open(pFileName, O_RDWR | O_CREAT | O_TRUNC)) < 0)
errorAndQuit(2);
fchmod(ret, S_IRUSR | S_IWUSR);
return ret;
}
At the top of my file, I have the following includes:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/stat.h>
#include <fcntl.h>
When compiling: the compiler spits out:
warning: implicit declaration of function ‘fchmod’
I'm including all of the correct files, yet getting this warning. The program runs fine, even with the warning.
By a happy coincidence, your question is directly answered by the feature_test_macros(7)
manpage:
Specification of feature test macro requirements in manual pages
When a function requires that a feature test macro is
defined, the manual page SYNOPSIS typically includes a note
of the following form (this example from the chmod(2) manual
page):
#include <sys/stat.h>
int chmod(const char *path, mode_t mode);
int fchmod(int fd, mode_t mode);
Feature Test Macro Requirements for glibc (see
feature_test_macros(7)):
fchmod(): _BSD_SOURCE || _XOPEN_SOURCE >= 500
The || means that in order to obtain the declaration of
fchmod(2) from <sys/stat.h>, either of the following macro
definitions must be made before including any header files:
#define _BSD_SOURCE
#define _XOPEN_SOURCE 500 /* or any value > 500 */
Alternatively, equivalent definitions can be included in the
compilation command:
cc -D_BSD_SOURCE
cc -D_XOPEN_SOURCE=500 # Or any value > 500