I am quite new to bash (barely any experience at all) and I need some help with a bash script.
I am using docker-compose to create multiple containers - for this example let's say 2 containers. The 2nd container will execute a bash command, but before that, I need to check that the 1st container is operational and fully configured. Instead of using a sleep command I want to create a bash script that will be located in the 2nd container and once executed do the following:
I found out how to do this in Java, but if I need to do this in a bash script.
The docker-containers have alpine as an operating system, but I updated the Dockerfile to install bash.
I tried this solution, but it does not work.
#!/bin/bash
[command to be executed] > allout.txt 2>&1
until
tail -n 0 -F /path/to/file | \
while read LINE
do
if echo "$LINE" | grep -q $string
then
echo -e "$string found in the console output"
fi
done
do
echo "String is not present. Executing command again"
sleep 5
[command to be executed] > allout.txt 2>&1
done
echo -e "String is found"
Just:
while :; do
# 1. Execute a command and log the console output in a file
command > output.log
# TODO: handle errors, etc.
# 2. Read that file and check if a String is present.
if grep -q "searched_string" output.log; then
# Once I find the string I am looking for I want to exit the loop
break;
fi
# 3. If the string is not present I want to execute the same command again until I find the String I am looking for
# add ex. sleep 0.1 for the loop to delay a little bit, not to use 100% cpu
done
# ...and execute a different command
different_command
You can timeout a command with timeout.
Notes: