I have 3 Localizable files in my project Localizable.string(English), Localizable.string(German) and Localizable.string(French) with several keys and values of form localizationKey1 = "Text1 in english";
. I want them to be converted in a single json file in format
{
"localizationKey1": {
"en": "Text1 in english",
"de": "Text1 in german",
"fr": "Text1 in french"
},
"localizationKey2": {
"en": "Text2 in english",
"de": "Text2 in german",
"fr": "Text2 in french"
} and so on depending on number of keys
}
How do I go about it?
EDIT: I was able to the required JSON format based on the answer by @Francis but the orders of the outer and inner keys are messed up. Is there any way to order them?
Try this
let path1 = (Bundle.main.path(forResource: "Localizable", ofType: "strings", inDirectory: nil, forLocalization: "en"))
let path2 = (Bundle.main.path(forResource: "Localizable", ofType: "strings", inDirectory: nil, forLocalization: "de"))
let path3 = (Bundle.main.path(forResource: "Localizable", ofType: "strings", inDirectory: nil, forLocalization: "fr"))
let dict1 = NSDictionary(contentsOfFile: path1!)
let dict2 = NSDictionary(contentsOfFile: path2!)
let dict3 = NSDictionary(contentsOfFile: path3!)
var newDict = [String : Any]()
for (key, value) in dict1! {
var value2 = ""
var value3 = ""
if let keyVal = dict2?[key] as? String {
value2 = keyVal
}
if let keyVal = dict3?[key] as? String {
value3 = keyVal
}
let tempDict = ["en": value, "de": value2, "fr": value3]
newDict["\(key)"] = tempDict
}
do {
let data = try JSONSerialization.data(withJSONObject: newDict, options: .prettyPrinted)
let dataString = String(data: data, encoding: .utf8)!
print(dataString) //This will give you the required JSON format
} catch {
print("JSON serialization failed: ", error)
}