I have using RUCKUS API for changing color of lamp and I need to convert color from RGB to XY to call an API.
I have tried this code:
1) Get the RGB values from your color object and convert them to be between 0 and 1
function rgb_to_cie(red, green, blue)
{
//Apply a gamma correction to the RGB values, which makes the color more vivid and more the like the color displayed on the screen of your device
var red = (red > 0.04045) ? Math.pow((red + 0.055) / (1.0 + 0.055), 2.4) : (red / 12.92);
var green = (green > 0.04045) ? Math.pow((green + 0.055) / (1.0 + 0.055), 2.4) : (green / 12.92);
var blue = (blue > 0.04045) ? Math.pow((blue + 0.055) / (1.0 + 0.055), 2.4) : (blue / 12.92);
//RGB values to XYZ using the Wide RGB D65 conversion formula
var X = red * 0.664511 + green * 0.154324 + blue * 0.162028;
var Y = red * 0.283881 + green * 0.668433 + blue * 0.047685;
var Z = red * 0.000088 + green * 0.072310 + blue * 0.986039;
//Calculate the xy values from the XYZ values
var x = (X / (X + Y + Z)).toFixed(4);
var y = (Y / (X + Y + Z)).toFixed(4);
if (isNaN(x))
x = 0;
if (isNaN(y))
y = 0;
return [x, y];
}
but it didn't provide a proper solution.
SO if i pass r:182 g: 255 B: 65 as this then I got x as 22932 and y as 35249 (AS PER DOC OF API.)
How can I do that?
I got the solution and here I attached the answer if you're looing for,
let red = 100
let green = 100
let blue = 100
let redC = (red / 255)
let greenC = (green / 255)
let blueC = (blue / 255)
console.log(redC, greenC , blueC)
let redN = (redC > 0.04045) ? Math.pow((redC + 0.055) / (1.0 + 0.055), 2.4): (redC / 12.92)
let greenN = (greenC > 0.04045) ? Math.pow((greenC + 0.055) / (1.0 + 0.055), 2.4) : (greenC / 12.92)
let blueN = (blueC > 0.04045) ? Math.pow((blueC + 0.055) / (1.0 + 0.055), 2.4) : (blueC / 12.92)
console.log(redN, greenN, blueN)
let X = redN * 0.664511 + greenN * 0.154324 + blueN * 0.162028;
let Y = redN * 0.283881 + greenN * 0.668433 + blueN * 0.047685;
let Z = redN * 0.000088 + greenN * 0.072310 + blueN * 0.986039;
console.log(X, Y, Z)
let x = X / (X + Y + Z);
let y = Y / (X + Y + Z);
X = x * 65536
Y = y * 65536