Given the input from example1 on page http://michael.dipperstein.com/lzw/#example1, I am unable to get the correct result:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "lzw.h"

void print_hex(unsigned char str[], int len) 
{
    int idx;

    for (idx = 0; idx < len; idx++)
        printf("%02x", str[idx]);
}

int main()
{
    FILE *fpIn;             /* pointer to open input file */
    FILE *fpOut;            /* pointer to open output file */
    FILE *fptr;

    char test_str_lzw[] = { "this_is_his_thing" };
    fptr = fopen("lzw_in_test.txt", "wb");
    fwrite(test_str_lzw, sizeof(char), strlen(test_str_lzw), fptr);
    fclose(fptr);

    fpIn = fopen("lzw_in_test.txt", "rb");
    fpOut = fopen("lzw_out.txt", "wb");

    LZWEncodeFile(fpIn, fpOut);

    fclose(fpIn);
    fclose(fpOut);

    // Getting the results from file
    if ((fptr = fopen("lzw_out.txt", "rb")) == NULL) {
        printf("Error! opening file");
        // Program exits if file pointer returns NULL.
        exit(1);
    }

    unsigned char lzw_out[256];
    memset(lzw_out, 0, 256);

    size_t num;
    num = fread(lzw_out, sizeof(unsigned char), 256, fptr);


    fclose(fptr);

    unsigned int lzw_size = num;
    printf("LZW out size: %d\n", lzw_size);
    printf("LZW out data: \n");
    print_hex(lzw_out, lzw_size);
    printf("\n");

    return(0);
}

Expected result in Hex:

0x74 0x68 0x69 0x73 0x5F 0x102 0x5F 0x101 0x103 0x100 0x69 0x6E 0x67

Result I'm getting in Hex:

0x74 0x34 0x1A 0x4E 0x65 0xF0 0x15 0x7C 0x03 0x03 0x80 0x5A 0x4D 0xC6 0x70 0x20

Can anyone help me to get output file like from the example?

Regards.