template<typename T>
class A
{
public:
A(T &t)
: t_(t){}
T t_;
};
int main()
{
int value;
A<decltype(value)> a(value);
// what I wish for : A a(value);
// which does not compile "missing template argument before 'a'"
}
Is there a way in the declaration of A (or somewhere else) to hint the compiler that T should be automatically resolved to the type passed to the constructor ?
(ideally c++11, but happy to hear about less old versions)
In C++11 you can create a simple make_A function like this:
#include <iostream>
template <typename T>
class A {
public:
A(T &t) : t_(t) {}
T t_;
};
template <typename T>
A<T> make_A(T&& t) {
return A<T>(std::forward<T>(t));
}
int main() {
int value = 0;
auto a = make_A(value);
return 0;
}