How do I pop the first n elements of a list and append these to a different list?
so, for example.
mylist = []
n = 3
mainlist = [5,4,3,2,1]
How would I make it so I have
mainlist = [2,1]
mylist = [5,4,3]
I've tried the following but it doesn't work as the placement of the elements are changing after each loop:
for i in list(range(n)):
mylist.append(mainlist.pop(i))
You could just slice the list:
mainlist = [5,4,3,2,1]
n = 3
mainlist, mylist = mainlist[:n], mainlist[n:]
Keep in mind that for slicing, the first index is inclusive, while the second is exclusive, so mainlist wouldn't contain index 3 but mylist would.