i have a list of key=>value pairs from a JSON squirt. i sorted the array and i'm left with the following (excerpted relevant cases because they go as high as 92):
dir1summary
dir10summary
dir1summarydue
dir10summarydue
directive1
directive10
directivecode1
directivecode10
what i need to do is: 1) place all the digits at the end and 2) pad them to 2 digits (01,02,&c) so the list ends up looking like this:
directivesummary01
directivesummary10
directivesummarydue01
directivesummarydue10
directive01
directive10
directivecode01
directivecode10
i was hoping to do this with one REGEX statement given the obvious similarity in key names, but i got lost. here's what i have so far:
dir((\d{1,2}(summary|summarydue))|((ective\d{1,2})|(ectivecode\d{1,2})))
...aaaand i'm lost what to do next. how to move on? is there a better compact way to do this?
EDIT: this also means i have to replace 'dir' with 'directive'. it's implied in the result list, but i didnt' make a bullet item for it. also, the REGEX is all i was able to build at RegExer. thus the "lost what to do next" part.
dir
ective
ective
as capture group #1 (this accounts for optional substrings like summarydue
)directive
, then append capture group #1 (which may be empty), then capture group #3 (might also be empty), finally left pad capture group #2 with a zero to a maximum length of 2-digits and append that value to the end of the stringCode: (Demo)
$strings = [
'dir1summary',
'dir10summary',
'dir1summarydue',
'dir10summarydue',
'directive1',
'directive10',
'directivecode1',
'directivecode10',
];
var_export(
preg_replace_callback(
'/dir(?:ective)?(\D*)(\d+)(.*)/',
function ($m) {
return "directive{$m[1]}{$m[3]}" . str_pad($m[2], 2, "0", STR_PAD_LEFT);
},
$strings
)
);
Output:
array (
0 => 'directivesummary01',
1 => 'directivesummary10',
2 => 'directivesummarydue01',
3 => 'directivesummarydue10',
4 => 'directive01',
5 => 'directive10',
6 => 'directivecode01',
7 => 'directivecode10',
)
Alternatively, you could parse the string with sscanf()
, then print the isolated components in the desired format with printf()
.
Code: (Demo)
foreach ($strings as $string) {
sscanf($string, '%[^0-9]%d%s', $dir, $num, $str);
printf("%s%s%02d\n", str_pad($dir, 9, 'ective'), $str, $num);
}
// same result strings as above