[SOLVED] Bash - parsing ini file, finding section name by values within

Bash - parsing ini file, finding section name by values within

I have a config.ini file which looks like this (updated):

[group1]
base=100
hwadd=0x20
doorstatus=100
lock=101
bookingnr=010100
kode=1111
inuse=0

[group2]
base=100
hwadd=0x20
doorstatus=100
lock=102
bookingnr= 010101
kode=1111
inuse=0

[group3]
base=100
hwadd=0x20
doorstatus=100
lock=103
bookingnr=010103
kode=1111
inuse=0

[group4]
base=100
hwadd=0x20
doorstatus=100
lock=105
bookingnr=010105
kode=1111
inuse=0

[group5]
base=100
hwadd=0x20
doorstatus=100
lock=106
bookingnr=010106
kode=1111
inuse=0

[group6]
base=100
hwadd=0x20
doorstatus=100
lock=107
bookingnr=010107
kode=1111
inuse=0

[group7]
base=100
hwadd=0x21
doorstatus=100
lock=101
bookingnr=010108
kode=1111
inuse=0

[group8]
base=100
hwadd=0x21
doorstatus=100
lock=102
bookingnr=010109
kode=1111
inuse=0
...

I need to get the room number where 3 given values (base, hwadd, lock) match the script parameters. So lets say the bash script was called like this:

script.sh 100 0x20 105

the script would return 4 (since all 3 parameters match group4)

Finding a single value is a piece of cake

source config.ini

and every value is available under $valX but this is not parsing the section names so it is useless in this case..

Solution

You may use this awk:

val='100 0x20 105'

awk -F= -v vals="$val" 'BEGIN {
   n = split(vals, w, /[ \t]+/)
   for (i=1; i<=n; i++)
      values[w[i]] = 1
}
/^\[group[0-9]+]$/ {
   if (n == found)
      print grp
   delete seen
   found = 0
   grp = $0
   gsub(/^\[group|\]$/, "", grp)
}
NF == 2 && values[$2] && !seen[$2]++ {
   found++
}
END {
   if (n == found)
      print grp
}' file

Code Demo