My goal is simply to convert a string such as "1.2" to scientific notation without adding additional precision. The problem is that I always end up with superfluous 0s at the end of my output.
>>> input = "1.2"
>>> print '{:e}'.format(float(input))
1.200000e+00
I'm trying to figure out how to get just 1.2e+00. I realize I can specify precision in my format statement, but I don't want to truncate longer strings unnecessarily. I just want to suppress the training 0s.
I've tried using Decimal.normalize(), which works in all cases, except where e < 2.
>>> print Decimal("1.2000e+4").normalize()
1.2E+4
>>> print Decimal("1.2000e+1").normalize()
12
So that's better, except I don't want 12, I want 1.2e+1. :P
Any suggestions would be greatly appreciated!
Edit: To clarify, the input value has already been rounded appropriately to a predetermined length that is now unknown. I'm trying to avoid recalculating the appropriate formatting precision.
Basically, I could have input values of "1.23" and "1234.56", which should come out as "1.23e+0" and "1.23456e+3".
I may have to just check how long the input string is and use that to specify a precision manually, but I wanted to check and make sure I just wasn't missing something that could just prevent the exponential format from arbitrarily adding 0s.
Just going back through and cleaning up old questions. I ended up solving this by writing a little function to intuit the initial precision of a number and then using it to format the output result.
#used to determine number of precise digits in a string
def get_precision(str_value):
vals = str_value.split('.')
if (vals[0] == '0'):
return len(vals[1])
else:
return len(str_value) -1
# maintain same precision of incoming string on output text
class ExpDecorator(CurrencyDecorator):
def get_text(self):
text = self.decoratedCurrency.get_text()
return ('{:.' + str(get_precision(text)-1) + 'e}').format(float(text))
Not really the most elegant solution, but the task was kind of obnoxious to begin with and it got the job done.