This is what I have so far but it returns only one proxy because it rewrites over it x (however many proxies) times. I do not want to make a new file but instead rewrite proxies.txt with every proxy.
const fs = require("fs");
const formatProxies = () => {
const rawProxies = fs.readFileSync("./proxies.txt", "utf-8");
const split = rawProxies.trim().split("\n");
for (const p of split) {
const parts = p.trim().split(":");
const [ip, port, user, pass] = parts;
fs.writeFileSync(
"./proxies.txt",
user + ":" + pass + "@" + ip + ":" + port + "\r\n",
{ encoding: "utf8" }
);
}
};
formatProxies();
Does this work?
const fs = require("fs");
const formatProxies = () => {
const rawProxies = fs.readFileSync("./proxies.txt", "utf-8");
const split = rawProxies.trim().split("\n");
const lines = []
for (const p of split) {
const parts = p.trim().split(":");
const [ip, port, user, pass] = parts;
lines.push(user + ":" + pass + "@" + ip + ":" + port)
}
fs.writeFileSync(
"./proxies.txt",
lines.join("\r\n"),
{ encoding: "utf8" }
);
};
formatProxies();