List compiles, but gives warning: incompatible pointer type

#include<stdio.h>
#include<stdlib.h>

typedef struct
{
    int number;
    struct player *next;
}player;

player *newPlayer;
player *firstPlayer;
player *currentPlayer;

int main(void)
{
    newPlayer = malloc(sizeof(player));
    firstPlayer = newPlayer;
    currentPlayer = newPlayer;
    currentPlayer->next = NULL;
    printf("Please enter Head: ");
    scanf("%d", &currentPlayer->number);

    newPlayer = malloc(sizeof(player));
    currentPlayer->next = newPlayer;
    currentPlayer = newPlayer;
    currentPlayer->next = NULL;
    printf("Please enter second element: ");
    scanf("%d", &currentPlayer->number);


    currentPlayer = firstPlayer;
    while (currentPlayer)
    {
        printf("%d ", currentPlayer->number);
        currentPlayer = currentPlayer->next;
    }
    printf("\n");


}

The code compiles correctly, but I get these warnings:
warning: assignment from incompatible pointer type [-Wincompatible-pointer-types]
currentPlayer->next = newPlayer;
and
warning: assignment from incompatible pointer type [-Wincompatible-pointer-types]
currentPlayer = currentPlayer->next;
Why is that and how can I fix it?
Thank you in advance :)

When defining your struct, you omitted the struct name. By doing that, you actually created a generic struct, which can be referred to only by its typedef (alias).

typedef struct
{
    int number;
    struct player *next;
} player;

In this definition, player is just an alias to this generic struct.

To fix that, add the word player to the first line:

typedef struct player
{
    int number;
    struct player *next;
} player_t;

Now, you're able to refer the struct either by struct player, or by player_t.

Always remember that the keyword typedef is just for us, the programmers, for readability. Don't count on it to do some extra work.

EDIT: As mentioned in the comments, it's possible to use typedef struct player player and refer to the struct either by struct player or just plain player.