Get Shape for view dynamically in SwiftUI

Using Swift 5.2 I would like to create a function to dynamically change the Shape

I have a view like

import SwiftUI

struct CardView: View {
    let suit : Suite
    let rank : Rank
    var body: some View {
        getShape(suite: .heart)
        .fill(Color.red)  // .fill(suit.color)
        .frame(width: 100, height: 100)
     }
}

I would like to create a function with a protocol return type of Shape, I substituted my custom shaps for generic in the example below

func getShape(suite:Suite) -> Shape {
    switch suite {
    case .heart:
        return Circle() // Heart()
    case .diamond:
        return Rectangle() // Diamond()
    case .spade:
        return Circle() // Heart()
    case .club:
        return Circle() // Club()

    }
}

I cannot use an opaque type with some because I am returning different types and I get a compile error

Function declares an opaque return type, but the return statements in its body do not have matching underlying types 

Nor can I leave it as is with the protocol type because I get the error

Protocol 'Shape' can only be used as a generic constraint because it has Self or associated type requirements

Is there any way I can achieve this elegantly?

By combining @Asperi's answer with

struct AnyShape: Shape {
    init<S: Shape>(_ wrapped: S) {
        _path = { rect in
            let path = wrapped.path(in: rect)
            return path
        }
    }

    func path(in rect: CGRect) -> Path {
        return _path(rect)
    }

    private let _path: (CGRect) -> Path
}

I can change it to

func getShape(suite:Suite) -> some Shape {
    switch suite {
    case .club:
        return AnyShape(Club())
    case .diamond:
        return AnyShape(Diamond())
    case .heart:
        return AnyShape(Heart())

    case .spade:
        return AnyShape(Spade())
    }
}


struct CardView: View {
    let suit : Suite
    let rank : Rank
    var body: some View {

    getShape(suite: suit)
      .fill(Color.red)
      .frame(width: 100, height: 100)
 }