When tying to implement mySqrt function in C++, I used the exp() function like this:
int mySqrt(int x) {
// For x = 2147395600
cout << exp(0.5*log(x)) << " "; // It prints 46340
return exp(0.5*log(x)); // But returns 46339
}
I tried to google the reason for this behavior but could not find anything. I even tried using double but still the same output.
Any explanation for this?
With this code
#include <iostream>
#include <cmath>
#include <cstdio>
using std::cout;
int mySqrt(int x) {
// For x = 2147395600
cout << exp(0.5*log(x)) << " "; // It prints 46340
return exp(0.5*log(x)); // But returns 46349
}
int main(void) {
std::cout << mySqrt(2147395600) << "\n";
printf("%.30f\n", exp(0.5*log(2147395600)));
return 0;
}
46340 46339
46339.999999999978172127157449722290
It seems the value is rounded when passed to cout
while truncated when converted to int
.