How to convert Color Literal to cgColor in the Swift?

var CodeBackground = #colorLiteral(red: 0.1294117647, green: 0.1294117647, blue: 0.1960784314, alpha: 1)

cells?.layer.borderColor = //... how can i set this color literal to cgColor?

As I know how to convert that UIColor to cgColor in the Swift

as example

UIColor.black.cgColor

Bingo, but what about Color Literal to cgColor in the Swift

Thank you.

• As, You already know the simpler way of using colorLiteral as cgcolor, I'll jump to the other way of doing that...

• For that you need a Custom Function which gets the color-value(red , green , blue) from the colorLiteral , which is as below

  extension UIColor {
      func rgb() -> (red:Int, green:Int, blue:Int, alpha:Int)? {
      var fRed : CGFloat = 0
      var fGreen : CGFloat = 0
      var fBlue : CGFloat = 0
      var fAlpha: CGFloat = 0
      if self.getRed(&fRed, green: &fGreen, blue: &fBlue, alpha: &fAlpha) {
          let iRed = Int(fRed * 255.0)
          let iGreen = Int(fGreen * 255.0)
          let iBlue = Int(fBlue * 255.0)
          let iAlpha = Int(fAlpha)
  
          _ = (iAlpha << 24) + (iRed << 16) + (iGreen << 8) + iBlue
          return (red:iRed, green:iGreen, blue:iBlue, alpha:iAlpha)
      } else {
          // Could not extract RGBA components:
          return nil
      }
  }
  }
  //It's more convenient to use function in `UIColor` extension
  

• Now , after this function created you can convert colorliteral into cgColor as below...

  let CodeBackground = #colorLiteral(red: 0.1294117647, green: 0.1294117647, blue: 0.1960784314, alpha: 1)
  let rgblit = CodeBackground.rgb()
  let Converted_cgColor = CGColor(srgbRed: CGFloat(integerLiteral: rgblit!.red), green: CGFloat(integerLiteral: rgblit!.green), blue: CGFloat(integerLiteral: rgblit!.blue), alpha: CGFloat(integerLiteral: rgblit!.alpha))
  

• You can directly use Converted_cgColor like

  cells?.layer.borderColor = Converted_cgColor
  

HOPE IT HELPS