Rust allows formatted printing of variables this way:
fn main(){
let r:f64 = rand::random();
println!("{}",r);
}
But this doesn't work:
fn main(){
println!("{}",rand::random());
}
It shows up this error:
|
31 | println!("{}",rand::random());
| ^^^^^^^^^^^^ cannot infer type for type parameter `T` declared on the function `random`
Is it possible to use function return value directly with println!
?
Rust doesn't know what type rand::random
should be, so you can use the turbofish to provide a type hint:
println!("{}", rand::random::<f64>());