I have a QByteArray
containing 8 bits representing two floating-point numbers, what is the correct and simplest way to read QDataStream
to QVector<float>
?
Code:
QByteArray ByteFloatArray;
QVector<float> qVecfloat;
ByteFloatArray.append(0x41);
ByteFloatArray.append(0x31);
ByteFloatArray.append(0x99);
ByteFloatArray.append(0x9A); // 4 bits float == 11.1
ByteFloatArray.append(0x41);
ByteFloatArray.append(0x31);
ByteFloatArray.append(0x99);
ByteFloatArray.append(0x9A); // 4 bits float == 11.1
QDataStream myStream(ByteFloatArray);
myStream.setFloatingPointPrecision(QDataStream::SinglePrecision);
myStream >> qVecfloat;
Code above gives:
STD:: bad_alloc at memory location"
I have read related problems, but I can't understand them properly to implement it in my case.
Below is my current solution, but I think it is over complicated and there is a simpler way to do that:
QVector<float> qVecfloat;
float myFloat;
for (int i = 0; i < 2; i++) {
QDataStream myStream(ByteFloatArray);
myStream.setFloatingPointPrecision(QDataStream::SinglePrecision);
myStream >> myFloat;
qVecfloat.append(myFloat);
ByteFloatArray.remove(0, 4);
qDebug() << "size " << qVecfloat.size() << " : " << qVecfloat;
}
You can use QDataStream::atEnd() in a loop and read the float
data like this :
QDataStream myStream( ByteFloatArray );
myStream.setFloatingPointPrecision( QDataStream::SinglePrecision );
float f = 0.0f;
while ( !myStream.atEnd() )
{
myStream >> f;
qVecfloat.append( f );
}
qDebug() << qVecfloat;
Output:
QVector(11.1, 11.1)