I am searching for the most efficient way to multiply two aligned int16_t arrays whose length can be divided by 16 with AVX2.
After multiplication into a vector x
I started with _mm256_extracti128_si256
and _mm256_castsi256_si128
to have the low and high part of x
and added them with _mm_add_epi16
.
I copied the result register and applied _mm_move_epi64
to the original register and added both again with _mm_add_epi16
. Now, I think that I have:
-, -, -, -, x15+x7+x11+x3, x14+x6+x10+x2, x13+x5+x9+x1, x12+x4+x8+x0
within the 128bit register. But now I am stuck and don't know how to efficiently sum up the remaining four entries and how to extract the 16bit result.
Following the comments and hours of google my working solution:
// AVX multiply
hash = 1;
start1 = std::chrono::high_resolution_clock::now();
for(int i=0; i<2000000; i++) {
ZTYPE* xv = al_entr1.c.data();
ZTYPE* yv = al_entr2.c.data();
__m256i tres = _mm256_setzero_si256();
for(int ii=0; ii < MAX_SIEVING_DIM; ii = ii+16/*8*/)
{
// editor's note: alignment required. Use loadu for unaligned
__m256i xr = _mm256_load_si256((__m256i*)(xv+ii));
__m256i yr = _mm256_load_si256((__m256i*)(yv+ii));
const __m256i tmp = _mm256_madd_epi16 (xr, yr);
tres = _mm256_add_epi32(tmp, tres);
}
// Reduction
const __m128i x128 = _mm_add_epi32 ( _mm256_extracti128_si256(tres, 1), _mm256_castsi256_si128(tres));
const __m128i x128_up = _mm_shuffle_epi32(x128, 78);
const __m128i x64 = _mm_add_epi32 (x128, x128_up);
const __m128i _x32 = _mm_hadd_epi32(x64, x64);
const int res = _mm_extract_epi32(_x32, 0);
hash |= res;
}
finish1 = std::chrono::high_resolution_clock::now();
elapsed1 = finish1 - start1;
std::cout << "AVX multiply: " <<elapsed1.count() << " sec. (" << hash << ")" << std::endl;
It is at least the fastest solution so far: