I think the left-recursion for this grammar is not removable. Correct me if I am wrong. α is Alpha that is a Non-terminal ε is Epsilon.
Left recursion can be removed from the grammar; Here is the grammar without left recursion:
A -> A' | ε
A' -> α A
You could also do how @Mephy did with right recursion:
A -> α A | ε
Note that (as @Mephy said) this grammar is just zero or more α
s (α*
).