all.
I'm trying to write a simple SPARQL query generator to fetch all rdf:type
relations of a specific DBPedia resource.
query = """SELECT * WHERE {{ <""" + resource """> rdfs:type ?subject.}}"""
This yields the Query
SELECT * WHERE {{ <http://dbpedia.org/page/Energy> rdfs:type ?subject.}}
But the query returns empty. What am I doing wrong? The DBPedia entry clearly has rdfs:type
relations:
owl:Thing
dbo:Building
yago:Abstraction100002137
yago:Assets113329641
yago:NaturalResource113332009
yago:Possession100032613
yago:Relation100031921
yago:Resource113331778
yago:WikicatNaturalResources
Thanks in advance!
Change the energy address from page
to resource
, the query looks like this (in addition, I suggest you to use the a
instead of therdf:type
):
SELECT * WHERE {{ <http://dbpedia.org/resource/Energy> a ?subject.}}
In order to avoid this issue, chech the exact resurces addresses in a raw data format. For example, the XML triples can be reviewed with a web browser from the dbpedia webpage. http://dbpedia.org/page/Energy, in the top bar there is a button named formats.