bind non static templated member function in derived class

#include <functional>
#include <iostream>

class Plain {
   public:
    template <typename Type>
    void member_function(const Type& s) {
        std::cout << "Recived: " << s << std::endl;
    }
};

template <typename Type>
class Templated : private Plain {
   public:
};

int main() {
    Plain b;
    b.member_function<int>(10); // done!
    Templated<int> d;
    // d.member_function();  /* how to achive this */

    return 0;
}

I am trying to call the member function in class Plain by two method:

1. createing non-templated class and padding type while calling function

Plain p;
p.member_function<int>();

2. passing type while creating class and calling without template param

Templated<int> t;
t.member_function(); // achive this

I tried doing binding the function in derived class like

struct Plain{
    template<typename T>
    static void member_function(const T& s){std::cout << s << std::endl;}
}

template<typename T>
struct Templated : private Plain {
    std::function<void(const T&)> print = Templated::Plain::member_function;
}

and after that I was able to do

Templated t<std::string>;
t.print();

I found a workaround

#include <functional>
#include <iostream>
using namespace std::placeholders;

struct Test {
    template <typename Type>
    void foo(const Type&) {
        std::cout << "I am just a foo..." << std::endl;
        return;
    }
};

template <typename T>
struct Foo {
   private:
    Test* obj;

   public:
    Foo() : obj(new Test) {}
    std::function<void(const int&)> foo = std::bind(&Test::foo<T>, obj, _1);
    ~Foo() { delete obj; }
};

int main() {
    Foo<int> me;
    me.foo(10);

    Test t;
    t.foo<int>(89);

    std::cout << std::endl;
    return 0;
}