I have a vector with timestamps as following:
1521753105.031429052352905
1521753105.081429004669189
1521753105.131428956985474
1521753105.181428909301758
1521753105.231429100036621
1521753105.281429052352905
1521753105.331429004669189
1521753105.381428956985474
1521753105.431428909301758
1521753105.481429100036621
1521753105.531429052352905
1521753105.581429004669189
The current time is:
1521753105.231428861618042
which is in between the 4th and 5th values.
How to determine the lower and upper index to the current time?
One liner trick!
A=%[your numbers]
v=%the value to find its position
braket=find(sort([A,v])==v)+[-1 0]
Assumes that A
was sorted originally, of course