Hope your days are going well :)
I am learning python recently with code academy site, and they gave me an example about zip() and append().
last_semester_gradebook = [("politics", 80), ("latin", 96), ("dance", 97), ("architecture", 65)]
subjects = ["physics", "calculus", "poetry", "history"]
grades = [98, 97, 85, 88]
subjects.append("computer science")
grades.append(100)
gradebook = zip(subjects, grades)
#This code is the problem
gradebook.append(("visual arts", 93))
print(list(gradebook))
This is the code I made but it gives me an error.
Traceback (most recent call last):
File "script.py", line 9, in <module>
gradebook.append(("visual arts", 93))
AttributeError: 'zip' object has no attribute 'append'
I would search for the error first for normal case, but the problem is, the code I wrote is exactly same as the code they gave me as an solution. That is why I am confused and asking here. Is it the error of the site or the solution is wrong?
Thank you for your attention
The problem is that zip is an iterator, not a sequence. I suspect that you have some old or untested code, not compatible with the current Python version. You zip result is usable as the target of a for statement, but has no append attribute -- it's a special type of function.
The conversion is easy enough: make a list from it earlier:
gradebook = list(zip(subjects, grades))
#This code is the problem
gradebook.append(("visual arts", 93))
print(gradebook)