Trying to simplify Karnaugh Map with only four groups of "True" Indicators
In the included screenshot, I am trying to derive the simplest boolean function. I used these four groups of ones to derive the different variable groups. According to the solution in my book, I don't have the correct four groups, but it does seem to be a grouping of four and not five. Does anyone see a grouping scenario I might have missed? I tried wrapping around but that doesn't seem to help either.
My final function of w, x, y, z was the following and it is apparently not the solution:
F (w, x, y, z) = w'x'z + w'yz' + xy' + wz
Solution
My solution is
F(w, x, y, z) = x y' + w z + x' z + w' y z'
Your term w'x'z can be slimmed down (or merged) to x'z as a disjunction of w'x'z and wx'z.
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