I'm currently using CyLP
package in Python for mixed-integer linear programming. However, I'm not able to initialize integer variables. According to the documentation, I have passed isInt = True
to addVariable
method but it does nothing.
A minimal example of my program is shown below. The optimal value should be 2 when x = y = 1
, but the result is not as expected.
import cylp
from cylp.cy import CyClpSimplex
print(cylp.__version__) # 0.91.0
s = CyClpSimplex()
x = s.addVariable('x', 1, isInt = True)
y = s.addVariable('y', 1, isInt = True)
s += x >= 0.5
s += y >= 0.7
s.objective = x + y
s.optimizationDirection = 'min'
s.primal()
# Clp3002W Empty problem - 0 rows, 2 columns and 0 elements
# Clp0000I Optimal - objective value 1.2
x_opt = s.primalVariableSolution['x'][0]
y_opt = s.primalVariableSolution['y'][0]
print(x_opt, y_opt) # 0.5, 0.7
Is there any other way to initialize integer variables in CyLP
? Or I'm missing something about addVariable
method?
By the way, I wonder what Clp3002W Empty problem
means in the output of s.primal()
.
Thanks in advance.
This is a bit mean.
Clp is a Linear-Programming solver while you are trying to do Mixed-Integer-Programming.
You will need to use Cbc which is built on top of Clp (same person / same people). I think, that one can recognize that most of this is a one-man project over decades (unintuitive design; maybe).
Yes, CyLp is based on Cbc, but usage still needs care!
Assuming, that your variable-definitions are okay (did not check), you will need to do something like:
# model = CyClpSimplex()
# ...
cbcModel = model.getCbcModel() # Clp -> Cbc model / LP -> MIP
status = cbcModel.solve() #-> "Call CbcMain. Solve the problem
# "using the same parameters used
# "by CbcSolver."
# This deviates from cylp's docs which are sparse!
# -> preprocessing will be used and is very important!
See also this wrapper:
if data[s.BOOL_IDX] or data[s.INT_IDX]:
# MIP
# Convert model
cbcModel = model.getCbcModel()
# cylp: /cylp/cy/CyCbcModel.pyx#L134
# Call CbcMain. Solve the problem using the same parameters used by
# CbcSolver. Equivalent to solving the model from the command line
# using cbc's binary.
cbcModel.solve()
status = cbcModel.status
else:
# LP
# cylp: /cylp/cy/CyClpSimplex.pyx
# Run CLP's initialSolve. It does a presolve and uses primal or dual
# Simplex to solve a problem.
status = model.initialSolve()
I wrote these things a lot of time ago, therefore i cannot give you exact details (background behind these calls and the comments).
But in general: it's hard to grasp what exactly is happening internally in Cbc (although there was some work in improving the API i think; probably NOT reflected in Cylp though). For example: it's not trivial to use Cbc from code in the same way as the Cbc executable behaves.
By the way, I wonder what Clp3002W Empty problem means in the output of s.primal().
Clp3002W Empty problem - 0 rows, 2 columns and 0 elements
My interpretation:
Your (transformed) model has no constraints. You added constraints to enforce variable-bounds but Clp/Cbc is advanced enough (it's very very advanced) to transform these constraints into variable-bounds (no constraints anymore!), which are handled by special treatment in the Simplex-Routine.
0 rows = 0 constraints
0 elements = 0 non-zero elements in your constraint-matrix of size
rows * cols = 0 * 2 = 0