pythonpython-3.xconditional-operatorwalrus-operator

What is the correct syntax for Walrus operator with ternary operator?


Looking at Python-Dev and StackOverflow, Python's ternary operator equivalent is:

a if condition else b

Looking at PEP-572 and StackOverflow, I understand what Walrus operator is:

:=

Now I'm trying to to combine the "walrus operator's assignment" and "ternary operator's conditional check" into a single statement, something like:

other_func(a) if (a := some_func(some_input)) else b

For example, please consider the below snippet:

do_something(list_of_roles) if list_of_roles := get_role_list(username) else "Role list is [] empty"

I'm failing to wrap my mind around the syntax. Having tried various combinations, every time the interpreter throws SyntaxError: invalid syntax. My python version is 3.8.3.

My question is What is the correct syntax to embed walrus operator within ternary operator?


Solution

  • Syntactically, you are just missing a pair of parenthesis.

    do_something(list_of_roles) if (list_of_roles := get_role_list(username)) else "Role list is [] empty"
    

    If you look at the grammar, := is defined as part of a high-level namedexpr_test construct:

    namedexpr_test: test [':=' test]
    

    while a conditional expression is a kind of test:

    test: or_test ['if' or_test 'else' test] | lambdef
    

    This means that := cannot be used in a conditional expression unless it occurs inside a nested expression.