djangodjango-modelsdjango-admindjango-contenttypes

How can I customize the display of a model using contenttypes in the admin?


I have these models:

class App(models.Model):
  name = models.CharField(max_length=100)

class ProjectA(models.Model):
  name = models.CharField(max_length=100)
  app  = models.ForeignKey(App)

class ProjectB(ProjectA):
  pass

class Attachment(models.Model):
  content_type    = models.ForeignKey(ContentType)
  object_id       = models.PositiveIntegerField()
  project         = generic.GenericForeignKey("content_type","object_id")
  file            = models.FileField(upload_to=".")

I'm registering all the models for the admin, and I'm unregistering Group, User and Site. The thing is, when I access the Attachment in the admin, I see it rendered like this:

admin for attachment

In the Content type select, I see this list:

select

The reason Attachment has a GenericForeignKey is because both ProjectA and ProjectB need to access it. I know that ProjectA and ProjectB are identical, but it's a requirement that they are stored in 2 separate tables. How could I made the Attachment class useable from the admin? I know how to use contenttypes from normal views, but from the admin not.

In the Attachment class I would only like to have a select for Project A or Project B, and then a list of all Project A's or all Project B's, followed by the file that I want to attach.

Is such a thing possible from the Admin? Will I need to show the user the Object Id column?


Solution

  • if I'm not wrong, you want this. http://code.google.com/p/django-genericadmin/

    my advice will work differently. you will add a little more form in ProjectA, ProjectB as inline. in your admin.py

    from django.contrib import admin
    from django.contrib.contenttypes import generic
    
    from myproject.myapp.models import Attachment, ProjectA, ProjectB
    
    class Attachmentline(generic.GenericTabularInline): #or generic.GenericStackedInline, this has different visual layout.
        model = Attachment
    
    class ProjectAdmin(admin.ModelAdmin):
        inlines = [
            Attachmentline,
        ]
    
    admin.site.register(ProjectA, ProjectAdmin)
    admin.site.register(ProjectB, ProjectAdmin)
    

    go your ProjectA or ProjectB admin and see new admin.

    this isn't what you want but it can help you. otherwise you need check first link.