If I throw a JavaScript exception myself (eg, throw "AArrggg"
), how can I get the stack trace (in Firebug or otherwise)? Right now I just get the message.
edit: As many people below have posted, it is possible to get a stack trace for a JavaScript exception but I want to get a stack trace for my exceptions. For example:
function foo() {
bar(2);
}
function bar(n) {
if (n < 2)
throw "Oh no! 'n' is too small!"
bar(n-1);
}
When foo
is called, I want to get a stack trace which includes the calls to foo
, bar
, bar
.
Edit 2 (2017):
In all modern browsers you can simply call: console.trace();
(MDN Reference)
Edit 1 (2013):
A better (and simpler) solution as pointed out in the comments on the original question is to use the stack
property of an Error
object like so:
function stackTrace() {
var err = new Error();
return err.stack;
}
This will generate output like this:
DBX.Utils.stackTrace@http://localhost:49573/assets/js/scripts.js:44
DBX.Console.Debug@http://localhost:49573/assets/js/scripts.js:9
.success@http://localhost:49573/:462
x.Callbacks/c@http://localhost:49573/assets/js/jquery-1.10.2.min.js:4
x.Callbacks/p.fireWith@http://localhost:49573/assets/js/jquery-1.10.2.min.js:4
k@http://localhost:49573/assets/js/jquery-1.10.2.min.js:6
.send/r@http://localhost:49573/assets/js/jquery-1.10.2.min.js:6
Giving the name of the calling function along with the URL, its calling function, and so on.
Original (2009):
A modified version of this snippet may somewhat help:
function stacktrace() {
function st2(f) {
return !f ? [] :
st2(f.caller).concat([f.toString().split('(')[0].substring(9) + '(' + f.arguments.join(',') + ')']);
}
return st2(arguments.callee.caller);
}