I have an array A,
array([[ 1, 2, 25],
[ 3, 4, 23],
[ 2, 6, 55],
[ 9, 7, 78],
[11, 5, 47]])
I changed the last column of the array, supposedly degree values (25,23,55,78,47) to radians.
its quite easy to do it, I did:
A_rad[:,2] = np.pi/180 *A[:,2]
you can also use np.radians, the output is:
array([[ 1, 1, 0],
[ 2, 3, 0],
[ 3, 2, 0],
[ 9, 5, 0],
[11, 3, 0]])
surely the last columns need to be changed, but not to zeros, i changed also the data type from int to float, the output were only 0., I need at least 3 decimals places in order to solve my problems.
The last column should give output as array([0.4363, 0.4014, 0.9599, 1.3614, 0.8203]). The thing is python doesn't save the decimals in the memory, so even if i multiply it always gives 0.
Is python able to do it?
any ideas.
You should cast your array to float:
import numpy as np
A = np.array([
[ 1, 2, 25],
[ 3, 4, 23],
[ 2, 6, 55],
[ 9, 7, 78],
[11, 5, 47]
]).astype(float)
A[:,2] = np.radians(A[:,2])
print(A)
This produces:
[[ 1. 2. 0.43633231]
[ 3. 4. 0.40142573]
[ 2. 6. 0.95993109]
[ 9. 7. 1.36135682]
[11. 5. 0.82030475]]
BTW: Instead of casting, you could also define the data type during initialization like so: A = np.array([...], dtype=float)