How to pass non-static member function as template argument to another member function?

I want to do something like this:

struct S
{
   void mf() {};

   template <auto f>
   void func()
   {
      f();
   }
};

int main()
{
   S x;
   x.func<x.mf>();
}

However, these are the errors:

error: no matching function for call to 'S::func<x.S::mf>()'`
note: candidate: 'template<auto f> void S::func()'
note:   template argument deduction/substitution failed:
error: could not convert 'x.S::mf' from '<unresolved overloaded function type>' to 'void (S::*)()'

I am not sure I understand what I am doing wrong.

Why is x.mf not resolved since I already instantiated x? And how do I make this work?

Calling member functions through a pointer can be so tricky.

You want to pass a member function pointer to S::mf like so:

struct S
{
    void mf () {std::cout << "called mf\n";};

    template <auto f>
    void func ()
    {
        (this->*f)(); 
    }
};

int main()
{
    S x;
    x.func<&S::mf>();
}