My Interrupt is not updating my value to my main, how should i set up my Interrupt?

Im trying to build a program that has a scannerlight with at least 5 leds and one button connected to an external interrupt pin. A single button press (and release) to start the scanner light. Pressing (and releasing) stops the scanner light again (and so on...).

• I have a ground side switch on PD2
• i have my LEDS on pin PD3,PD4,PD5,PD6 and PD7.
• Im useing ATMega328P

I know my towering light works when i press on the button the towering light stops but when i press again it feels like it doesnt return the value to 1.

My code:

#ifndef F_CPU                   
#define F_CPU 1000000UL         
#endif

#include <avr/io.h>
#include <util/delay.h>
#include <avr/interrupt.h>

#define BIT_IS_CLEAR(byte, bit) (!(byte & (1 << bit)))

volatile int value = 1;
int main(void)
{
    DDRD = 0b111110000;
    DDRD &= ~(1 << PD2);        // clear DDRD bit 2, sets PD2 (pin 4) for input
    PORTD |= (1 << PD2);        // set PD2/INT0 (pin 4) internal pull-up resistor
    
    
    PCICR = 0b00000100;
    PCMSK2 = 0b00000100;
    sei();
    
    while (value==1) //when value is 1 it should start having a towerlight
    {
        PORTD= 0x80;
        _delay_ms(15000);
        PORTD= 0x40;
        _delay_ms(15000);
        PORTD= 0x20;
        _delay_ms(15000);
        PORTD= 0x10;
        _delay_ms(15000);
        PORTD= 0x08;
        _delay_ms(15000);
        
    }

}


ISR(PCINT2_vect)
{

    if(BIT_IS_CLEAR(PIND, PD2) & value==1) {            // if switch is pressed (logic low)
        value=0;
        } else if(value == 0) { 
        value=1;
        } else {
        // ideally should never get here, but may occasionally due to timing
    }
}```

regarding:

while (value==1)
{
    ....
}

When value is 0 the loop is exited, execution then exits the program. This is a serious logic flaw in the program