how come every time you make a change to one reference of a array it does not make a change on another either though both point to the same object.
Example:
myArray = new Array(5,5,5);
Array2 = new Array(7,7,7);
alert(myArray) // still equals 5,5,5,`
[edit 12/2024] ... when a 13 year old answer comes to haunt you.
Array is a native Object. From it, you can create instances, either by using the Array function, by instantiating using the new keyword or using an Array literal ([...]).
So var myArr = new Array(5,5,5) creates an instance of Array. myArray is a reference to this instance.
The variable myArr is a brand new instance of Array. It has nothing to do with myArray.
When you create a copy of myArray, the copy will reference it's original and a change of one of the values of the copy will also change the value in the original.
const myArray = new Array(1, 2, 3, 4);
// create a copy:
const copyOfMyArray = myArray;
console.log(`myArray: [${myArray}], copyOfMyArray: [${copyOfMyArray}]`);
// change a value in the copy:
copyOfMyArray[0] = 42;
// copyOfMyArray is a reference to myArray
console.log(`myArray: [${myArray}], copyOfMyArray: [${copyOfMyArray}]`);
// it works both ways
myArray[1] = 42;
console.log(`myArray: [${myArray}], copyOfMyArray: [${copyOfMyArray}]`);