I need to apply two formulas on a dropdown field. How to apply both the formulas?I want to use the distinct funciton to avoid the duplicate values & the dropdown values depend on another column values. I have the formulas in hand but dont know how to apply both
you can just chain them like in most other languages fn1(fn2(x)).
Not knowing the second function i'll just assume it to be filter:
Distinct(Filter(MyTableVariable, MyFilterColumn = "MyFilterCriteria"), MyReturnValuesColumn)
an additional note: this code goes into the Items property of the dropdown