I need to apply two formulas on a dropdown field. How to apply both the formulas?I want to use the distinct funciton to avoid the duplicate values & the dropdown values depend on another column values. I have the formulas in hand but dont know how to apply both
you can just chain them like in most other languages fn1(fn2(x))
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Not knowing the second function i'll just assume it to be filter:
Distinct(Filter(MyTableVariable, MyFilterColumn = "MyFilterCriteria"), MyReturnValuesColumn)
an additional note: this code goes into the Items property of the dropdown