The question as below: Create a dictionary called char_d from the string stri, so that the key is a character and the value is how many times it occurs.
this is the code i tried:
stri = "what can I do"
char_d={}
lst=stri.split()
for wrd in lst:
for c in wrd:
if c not in char_d:
char_d[c]=0
char_d[c]+=1
the output i get is:
[('h', 1), ('o', 1), ('c', 1), ('t', 1), ('n', 1), ('d', 1), ('I', 1), ('a', 2), ('w', 1)]
the expected value should include: (' ',3)
i think the value should be including the space but how we do it?
What you proposed works. You can use get method of dictionary to be more pythonic.
stri = "what can I do"
char_d={}
#lst=stri.split()
#for wrd in stri:
for c in stri:
char_d[c] = char_d.get(c, 0) + 1
get(c, 0) will return 0 if c does not exist in the dict.
You can also use Counter from collections.
char_d = Counter(stri)