I have foreach loop that go through file, get path and replace it in the command for getting hashes:
$hash = @{}
...
defining variables here
...
foreach($line in $lines)
{
Get-FileHash $line -Algorithm md5 | format-list | Where { $_ } | Out-File -Width 200 'hash.txt' -Encoding ascii -Append
Get-FileHash $line -Algorithm sha256 | format-list | Where { $_ } | Out-File -Width 200 'hash.txt' -Encoding ascii -Append
Get-FileHash $line -Algorithm sha512 | format-list | Where { $_ } | Out-File -Width 200 'hash.txt' -Encoding ascii -Append
@('MD5','SHA256','SHA512') | % { Get-FileHash -Algorithm $_ $line } | export-csv hash.csv -Delimiter "," -Append
}
The problem which I'm facing with is that I have 2 empty lines on the beginning of file, and 4 empty lines on the end of file, here is the output:
Algorithm : MD5
Hash : xxx
Path : xxx
Algorithm : SHA256
Hash : xxx
Path : xxx
Algorithm : SHA512
Hash : xxx
Path : xxx
How should I get rid of empty lines on the beginning and the end of file?
You could format all output in one step, and then trim it before writing to file:
($lines | foreach {
foreach ($alg in ('MD5','SHA256','SHA512')) {
Get-FileHash $_ -Algorithm $alg
}
} | format-list | out-string).trim() | Out-File 'hash.txt' -Encoding ascii