In my Python code, I have a function with "try" and "except" statement:
for x in range (int(firstSocketEntry.get()), int(lastSocketEntry.get())+1): # Test will be done according to the range of the sockets
for attempt in range (int(attemptEntry.get())):
try:
print('Attempt: ' + str(attempt+1))
print('DUT: ' + str(x))
time.sleep(1)
client = HTTPClient('http://' + ipEntry.get() + port)
response = client.send(Request('test_is_alive', x), timeout=httpTimeOutEntry.get())
# response = request("http://" + ipEntry.get() + port, "test_is_alive", x)
time.sleep(1)
print(response.text)
print(response.data.result)
answer = response.data.result
logFile.write(time.strftime("%Y_%m_%d-%H_%M_%S\t\t") + str(x) + "\t\t" + str(answer) + "\t\t" + str(readVoltage()) + "\t\t" + str(readCurrent()) + "\n")
except:
print("Something went wrong!")
executeFunctionX()
else:
if (response.data.result==False):
print("\nAttempt " + str(attempt + 1) + " failed!")
else:
break
else:
print('\nAll attempts failed!')
If now something in the "try" statement goes wrong, the code continues at the "except" statement, which is the goal. How can I still get the error message (i.e.:
Traceback (most recent call last): File "C:\Users\pfra\AppData\Local\Programs\P six.raise_from(e, None) File "", line 3, in raise_from File "C:\Users\pfra\AppData\Local\Programs\P httplib_response = conn.getresponse())?
Because right now, I never know what exactly went wrong.
Any help is highly appreciated. Thanks a lot in advance. Regards
You will need to slightly modify your except:
.
See this:
>>> try:
... a
... except:
... print("Something went wrong!")
...
Something went wrong!
and compare it with:
>>> try:
... a
... except NameError as e:
... print(f"What went wrong is {e}")
...
What went wrong is name 'a' is not defined
If you do not know what exception your code may throw you can use except Exception as e:
. However, it makes sense to invest the time to understand what exceptions your code may throw.