I am trying to make an infix calculator for which I am currently trying to convert numbers entered in a character array to double.
here's my code:
#include <iostream>
#include<cmath>
using namespace std;
int main()
{
char exp[500];
const int SIZE = 100;
char temp[SIZE];
char op;
int strLen = 0, k, l, num = 0, fnum = 0;
double number = 0;
cin.getline(exp, 500,'\n');
int i = 0, j = 0, fpoint=0;
cout << exp;
for (i = 0, j = 0; exp[j] != 0; i++)
{
if (i % 2 == 0)
{
for (int m = 0; exp[m] != ','; m++) //stopped working
temp[m] = exp[m];
cout << temp;
for (k = 0; k < SIZE && temp[k] != 0; k++)
{
strLen = k;
if (temp[k] == '.')
fpoint = k + 1;
}
cout << fpoint<<endl;
cout << "strLen" << strLen;
for (k = 0; k <= fpoint; k++)
{
num = num + ((temp[fpoint - k] - '0') * pow(10, k));
}
for (k = fpoint + 1, l = 0; k <= strLen; k++, l++)
{
fnum = fnum + ((temp[strLen - l] - '0') * pow(10, l));
}
number = num + (fnum / pow(10, strLen - fpoint + 1));
cout << number;
j = j + strLen + 1;
}
else
{
char op = temp[j];
cout << op;
}
}
system("pause");
return 0;
}
sample input
2.5*3
It stops working and gives segmentation fault as an error on the marked position.
This line for (int m = 0; exp[m] != ','; m++) //stopped working
will always fail if there are no ,
characters since exp[m] != ','
will always be equal to true
and so will reach beyond the end of the array of exp
which triggers the "segmentation fault".