I have a list L = [1,2,3].
I perform the following on L:
lists:sublist(L,2) ++ [10] ++ lists:nthtail(3,L).
Instead of storing the result in a new list, I want to store the result in L itself. However, when I do so, I am getting the obvious error: ** exception error: no match of right hand side value [1,2,300]
I don't want to use a new variable, I want to rewrite in L itself. Is it possible?
No, Erlang has single assignment. To use an example from Armstrong, in C this works:
x = 5;
x = x + 10;
But in Erlang it is written:
X = 5;
X1 = X + 10;