Amdahl’s law states that a speed up of the entire system is
an_old_time / a_new_time
where the a_new_time
can be represented as ( 1 - f ) + f / s’
, where f
is the fraction of the system that is enhanced by some modification, and s’
is the amount by which that fraction of the system is enhanced. However, after solving this equation for s’
, it seems like there are many cases in which s’
is negative, which makes no physical sense.
Taking the case that s = 2
(a 100% increase in the speed for entire system) and f = 0.1
(a 10% of the system is impacted by some speed enhancement s’
), we solve for s’
by setting an_old time = 1
and s’ = f / ( f + 1 / s - 1 )
.
Plugging on the values for f
and s
, we find that :
s’ = 0.1 / ( 0.1 + 0.5 - 1 ) = 0.1 / -0.4
which means that the s’
value is negative.
How can this be possible, and what is the physical meaning of this? Also, how can I avoid negative s’
values when answering questions like these?
Amdahl's Law, also known as Amdahl's argument, is used to find the maximum expected improvement to an overall process when only a part of the process is improved.
1 | where S is the maximum theoretical Speedup achievable
S = __________________________; | s is the pure-[SERIAL]-section fraction
( 1 - s ) | ( 1 - s ) a True-[PARALLEL]-section fraction
s + _________ | N is the number of processes doing the [PAR.]-part
N |
Due to the algebra, the s + ( 1 - s ) == 1
, s being anything from < 0.0 .. 1.0 >
, there is no chance to get negative values here.
It is often applied in the field of parallel-computing to predict the theoretical maximum speedup achievable by using multiple processors. The law is named after Dr. Gene M. AMDAHL ( IBM Corporation ) and was presented at the AFIPS Spring Joint Computer Conference in 1967.
His paper was extending a prior work, cited by Amdahl himself as "... one of the most thorough analyses of relative computer capabilities currently published ...", published in 1966/Sep by prof. Kenneth E. KNIGHT, Stanford School of Business Administration. The paper keeps a general view on process improvement.
a SPEEDUP
BETWEEN
a <PROCESS_B>-[SEQ.B]-[PAR.B:N]
[START] and
[T0] [T0+tsA] a <PROCESS_A>-[SEQ.A]-ONLY
| |
v v
| |
PROCESS:<SEQ.A>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>|
| |
+-----------------------------------------+
| |
[T0] [T0+tsB] [T0+tsB+tpB]
| | |
v v v
|________________|R.0: ____.____.____.____|
| |R.1? ____.____| :
| |R.2? ____| : :
| |R.3? ____| : :
| |R.4? : : :
| |R.5? : : :
| |R.6? : : :
| |R.7? : : :
| | : : :
PROCESS:<SEQ.B>>>>>>>>>>|<PAR.B:4>: : :
| |<PAR.B:2>:>>>>: :
|<PAR.B:1>:>>>>:>>>>>>>>>: ~~ <PAR.B:1> == [SEQ]
: : :
: : [FINISH] using 1 PAR-RESOURCE
: [FINISH] if using 2 PAR-RESOURCEs
[FINISH] if using 4 PAR-RESOURCEs
( Execution time flows from left to right, from [T0]
.. to [T0 + ts1 + tp1]
.
The sketched order of [SEQ]
, [PAR]
sections was chosen just for illustrative purpose here, can be opposite, in principle, as the process-flow sections' durations ordering is commutative in principle )
The speedup of a { program | process }, coming from using multiple processors in parallel computing, was derived to be ( maybe to a surprise of audience ) principally limited by the very fraction of time, that was consumed for the non-improved part of the processing, typically the sequential fraction of the program processing, executed still in a pure [SERIAL]
process-schedulling manner ( be it due to not being parallelised per-se, or non-parallelisable by nature ).
For example, if a program needs 20 hours using a single processor core, and a particular portion of the program which takes one hour to execute cannot be parallelized ( having been processed in a pure-[SERIAL]
process-scheduling manner ) , while the remaining 19 hours (95%) of execution time can be parallelized ( using a true-[PARALLEL]
( not a "just"-[CONCURRENT]
) process-scheduling ), then out of the question the minimum achievable execution time cannot be less than that ( first ) critical one hour, regardless of how many processors are devoted to a parallelized process execution of the rest of this program.
Hence the Speedup
achievable is principally limited up to 20x, even if an infinite amount of processors would have been used for the [PARALLEL]
-fraction of the process.
See also:
CRI UNICOS has a useful command amlaw(1) which does simple number crunching on Amdahl's Law. ------------
On a CRI system type:
man amlaw
.1 1 S = lim ------------ = --- P->oo 1-s s s + --- P S = speedup which can be achieved with P processors s (small sigma) = proportion of a calculation which is serial 1-s = parallelizable portion
Speedup_overall
= 1 / ( ( 1 - Fraction_enhanced ) + ( Fraction_enhanced / Speedup_enhanced ) )
Articles to parallel@ctc.com (Administrative: bigrigg@ctc.com)
Archive: http://www.hensa.ac.uk/parallel/internet/usenet/comp.parallel
While Amdahl has formulated process-oriented speedup comparison, many educators keep repeating the formula, as if it were postulated for the multiprocessing process rearrangement, without taking into account also the following cardinal issues:
N
is not widely confirmed, ref. Dr. J. L. Gustafson, Jack Dongarra, et el, who claimed approaches with better than linear scaling in N
)Both of these group of factors have to be incorporated in the overhead-strict, resources-aware Amdahl's Law re-formulation, if it ought serve well to compare apples to apples in contemporary parallel-computing realms. Any kind of use of an overhead-naive formula results but in a dogmatic result, which was by far not formulated by Dr. Gene M. Amdahl in his paper ( ref. above ) and comparing apples to oranges have never brought anything positive to any scientific discourse in any rigorous domain.
1
S = __________________________; where s, ( 1 - s ), N were defined above
( 1 - s ) pSO:= [PAR]-Setup-Overhead add-on
s + pSO + _________ + pTO pTO:= [PAR]-Terminate-Overhead add-on
N
1 where s, ( 1 - s ), N
S = ______________________________________________ ; pSO, pTO
/ ( 1 - s ) \ were defined above
s + pSO + max| _________ , atomicP | + pTO atomicP:= further indivisible duration of atomic-process-block
\ N /
Due to reasons described above, one picture might be worth million words here. Try this, where a fully interactive tool for using the overhead-strict Amdahl's Law is cross-linked.