My assignment is to redirect a text file and do all sorts of operations on it , everything is working except I have a little problem :
so the main function that reads input is getline1():
char* getline1(){
char *LinePtr = (char*)malloc(sizeof(char*)*LINE);
int i = 0;
for ( ; (*(LinePtr+i) = getc(stdin)) != '\n' ; i++){}
*(LinePtr+i) = '\0';
return LinePtr;
}
it returns a pointer to char array of a single line,
so we know that a new line saparates with '\n' char,
previous problem I had is when I wrote the getline1() function like this :
for (int i = 0 ; Line[i] != '\n' ; i++){
Line[i] = getc(stdin);
}
as it logically it may be authentic the getc() is a streaming function and I saw online answers that this will not work didn't quite understand why.
anyway the big issue is that I need to know how many lines there are in the text so I can stop reading values , or to know from getline1() function that there is no next line left and Im done.
things we need to take for account : 1.only <stdio.h> <stdlib.h> need to be used 2.Im using Linux Ubuntu and gcc compiler 3.the ridirection goes like ./Run<input.txt
also I understand that stdin is a file pointer , didn't found a way that this can help me.
Thank you , Denis
You should check for the EOF
signal in addition to the newline
character, you should also check for that your index-1
is always smaller than LINE
to avoid overflow and also save space for the NULL terminator
.
#define LINE 100
char *my_getline(void)
{
size_t i = 0;
char *str = NULL;
int c = 0;
if ((str = malloc(LINE)) == NULL)
{
fprintf(stderr,"Malloc failed");
exit(EXIT_FAILURE);
}
while (i+1 < LINE && (c = getchar()) != EOF && c != '\n') /* Saving space for \0 */
{
str[i++] = c;
}
str[i] = '\0';
return str;
}