What I want to achieve:
What I've tried:
.txt file in a directory, write 'running' & 'not running' into the file while opening & exiting the window. And checking the file contents at very start. For ex:
When starting app: 1.) Check the file content, 2.) If file content is 'running', show warning & exit the app 3.) If file content is 'not running', write 'running' into the file & start app 4.) Write 'not running' into the file on exit.Issues I'm facing:
This method doesn't feel like the right way to achieve this.
If file item says 'not running', app shows warning and exits. While I want it to show already running instance.
File items not updated to 'not running' when app exits because of some error in code (because that part is never reached due to error)
Can anybody please help me out regarding this?
You can achieve something similar with the win32gui module. To install it type into CMD pip install pywin32. Now this is the code:
from win32 import win32gui
import sys
def windowEnumerationHandler(hwnd, top_windows):
top_windows.append((hwnd, win32gui.GetWindowText(hwnd)))
top_windows = []
win32gui.EnumWindows(windowEnumerationHandler, top_windows)
for i in top_windows:
if "Program" in i[1]: #CHANGE PROGRAM TO THE NAME OF YOUR WINDOW
win32gui.ShowWindow(i[0],5)
win32gui.SetForegroundWindow(i[0])
sys.exit()
from PyQt5.QtWidgets import QApplication, QWidget
def main():
#YOUR PROGRAM GOES HERE
app = QApplication(sys.argv)
w = QWidget()
w.setGeometry(500, 500, 500, 500)
w.setWindowTitle('Simple')
w.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Basically, at the beginning, the program gets the name of every open window. If the window name is equal to the name of the program, then it brings the program to the front and closes the program. If not, then it opens a new program.