So I am scraping this website with link : https://www.americanexpress.com/in/credit-cards/payback-card/ using beautiful soup and python.
link = 'https://www.americanexpress.com/in/credit-cards/payback-card/'
html = urlopen(link)
soup = BeautifulSoup(html, 'lxml')
details = []
for span in soup.select(".why-amex__subtitle span"):
details.append(f'{span.get_text(strip=True)}: {span.find_next("span").get_text(strip=True)}')
print(details)
Output:
['EARN POINTS: Earn multiple Points from more than 50 PAYBACK partners2and 2 PAYBACK Points from American\xa0Express PAYBACK Credit\xa0Card for every Rs.\xa0100 spent', 'WELCOME GIFT: Get Flipkart voucher worth Rs. 7503on taking 3 transactions within 60 days of Cardmembership', 'MILESTONE BENEFITS: Flipkart vouchers4worth Rs. 7,000 on spending Rs. 2.5 lacs in a Cardmembership yearYou will earn a Flipkart voucher4worth Rs. 2,000 on spending Rs. 1.25 lacs in a Cardmembership year. Additionally, you will earn a Flipkart voucher4worth Rs. 5,000 on spending Rs. 2.5 lacs in a Cardmembership year.']
As you can see in the output there are \xa0 characters that are to be eliminated from the string.
I tried to use replace function, but it isn't working out with the f string, since there is \ involved.
details.append(f'{span.get_text(strip=True)}: {span.find_next("span").get_text(strip=True).replace("\xa0","")}')
Is there any alternative to go about this ?
Any help is highly appreciated !!!
You can use unicodedata
to remove the \xa0
characters. It will not run when inluded in the f strings, but this will do:
from bs4 import BeautifulSoup
from unicodedata import normalize
link = 'https://www.americanexpress.com/in/credit-cards/payback-card/'
html = urlopen(link)
soup = BeautifulSoup(html, 'lxml')
details = []
for span in soup.select(".why-amex__subtitle span"):
a = normalize('NFKD', span.get_text(strip=True))
b = normalize('NFKD',span.find_next("span").get_text(strip=True))
details.append(f'{a}: {b}')
print(details)