Client:
int[] handshake_payload = {0x00,0x04,0x12A,0x01,0x06,0x135959}; //an array of hex values to be sent
for(int n:handshake_payload)
dataOutputStream.write(n);
dataOutputStream.flush();
Server:
int tag = dataInputStream.readUnsignedByte();
System.out.println("Tag:"+String.format("%02X", tag)); //prints Tag:00; this is fine
int len = dataInputStream.readUnsignedShort();
System.out.println("Len:"+String.format("%02X", len)); //prints Len: 42A , why not 412A (even when 412A
//fits in 16 bits of readUnsignedShort())
int val = dataInputStream.read();
System.out.println("Val:"+String.format("%02X", val)); //prints Val:01; fine
int valb = dataInputStream.readUnsignedByte();
System.out.println(String.format("%02X", valb)); //prints 06; fine
int vals = dataInputStream.readUnsignedByte();
System.out.println(String.format("%02X", vals)); // prints 59 , how do I read this in order to get the complete value 135959 , tried with readInt but throws EOFException, since end of stream reached before reading 4 bytes
Why is the last readUnsignedByte() returning 59 , & not 13 ?
The problem is on the writing end rather than the reading end.
Why is the last
readUnsignedByte()returning 59 , & not 13 ?
Because that is what was actually written. The write(int b) method is specified as follows:
"Writes the specified byte (the low eight bits of the argument
b) to the underlying output stream."
So write(0x135959) writes one byte: 0x59.
If you want to write the int as 4 bytes, use the writeInt(int) method instead.
If you want to write the int as 1 to 4 bytes without sending the non-significant leading zero bytes ... there isn't an API call to do that. You will need to implement it using a loop with some shifting and masking ... or similar.