I wish to replace the present value in column 'Manner' for all the words containing, 'kala', 'kalla' in column 'Filename' (the first two initials denote the Speaker) from "Sonorant' to "Liquid".
My idea is that it could be performed through 'dplyr' (probably 'grep') but don't know how to. This can be done in MS Excel but it will take a great amount of time by doing it manually.
Any help will be great. Thanks in advance.
Some of my data here:
Filename Consonant Place Manner
9 AK_kala.TextGrid Singleton Dental/alveolar Sonorant
10 AK_kalla.TextGrid Geminate Dental/alveolar Sonorant
14 AK_manni.TextGrid Geminate Dental/alveolar Sonorant
15 AK_rami.TextGrid Singleton Bilabial Sonorant
16 AK_rammi.TextGrid Geminate Bilabial Sonorant
20 AK_sune.TextGrid Singleton Dental/alveolar Sonorant
You can check for pattern in Filename
column and turn the Manner
column to 'Liquid'
.
df$Manner[grep('kall?a', df$Filename)] <- 'Liquid'
#Maybe this is more clear
#df$Manner[grep('kala|kalla', df$Filename)] <- 'Liquid'
df
# Filename Consonant Place Manner
#9 AK_kala.TextGrid Singleton Dental/alveolar Liquid
#10 AK_kalla.TextGrid Geminate Dental/alveolar Liquid
#14 AK_manni.TextGrid Geminate Dental/alveolar Sonorant
#15 AK_rami.TextGrid Singleton Bilabial Sonorant
#16 AK_rammi.TextGrid Geminate Bilabial Sonorant
#20 AK_sune.TextGrid Singleton Dental/alveolar Sonorant